(6x^2-4x-10)/(3x-5)

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Solution for (6x^2-4x-10)/(3x-5) equation: 


D( x )

3*x-5 = 0

3*x-5 = 0

3*x-5 = 0

3*x-5 = 0 // + 5

3*x = 5 // : 3

x = 5/3

x in (-oo:5/3) U (5/3:+oo)

(6*x^2-(4*x)-10)/(3*x-5) = 0

(6*x^2-4*x-10)/(3*x-5) = 0

6*x^2-4*x-10 = 0

2*(3*x^2-2*x-5) = 0

3*x^2-2*x-5 = 0

DELTA = (-2)^2-(-5*3*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)+2)/(2*3) or x = (2-64^(1/2))/(2*3)

x = 5/3 or x = -1

2*(x+1)*(x-5/3) = 0

(2*(x+1)*(x-5/3))/(3*x-5) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-5/3 )

x-5/3 = 0 // + 5/3

x = 5/3

x in { 5/3} 

x = -1

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